Bài tập chương II Đại số Lớp 8

BÀI TẬP 

Bai 1 Giải các phương trình sau:	
1. 	a)	3x – 2 = 2x – 3	b)	3 – 4y + 24 + 6y = y + 27 + 3y
	c)	7 – 2x = 22 – 3x	d)	8x – 3 = 5x + 12
	e)	x – 12 + 4x = 25 + 2x – 1	f)	x + 2x + 3x – 19 = 3x + 5
	g)	11 + 8x – 3 = 5x – 3 + x	h)	4 – 2x + 15 = 9x + 4 – 2x
2.	a)	5 – (x – 6) = 4(3 – 2x)	b)	2x(x + 2)2 – 8x2 = 2(x – 2)(x2 + 2x + 4) 
	c)	7 – (2x + 4) = – (x + 4)	d)	(x – 2)3 + (3x – 1)(3x + 1) = (x + 1)3
	e)	(x + 1)(2x – 3) = (2x – 1)(x + 5)	f)	(x – 1)3 – x(x + 1)2 = 5x(2 – x) – 11(x + 2)
	g)	(x – 1) – (2x – 1) = 9 – x	h)	(x – 3)(x + 4) – 2(3x – 2) = (x – 4)2	
	i) 	x(x + 3)2 – 3x = (x + 2)3 + 1	j)	(x + 1)(x2 – x + 1) – 2x = x(x + 1)(x – 1) 
3.	a)	1,2 – (x – 0,8) = –2(0,9 + x)	b)	3,6 – 0,5(2x + 1) = x – 0,25(2 – 4x) 
	c)	2,3x – 2(0,7 + 2x) = 3,6 – 1,7x 	d) 	0,1 – 2(0,5t – 0,1) = 2(t – 2,5) – 0,7
	e)	3 + 2,25x +2,6 = 2x + 5 + 0,4x	f)	5x + 3,48 – 2,35x = 5,38 – 2,9x + 10,42
4. 	a)	b) 	
	c)	d) 	
	e)	f) 	
	g)	h) 	
	i) 	k) 	
	m) 	n) 	
	p) 	q) 	
	r) 	s) 	
	t) 	u) 	
	v)	w)	
5.	a)	b)	
	c)	d)	
	e)	f)	
	g)	h)	
 6.
a) 	b) 
c) 

a) 	b) 
6.
a) 	b) 
c) 	d) 
e) 	f) 
g) 	h) 
i) 
Bài tập 2:
1.	a)	(3x – 2)(4x + 5) = 0	b)	(2,3x – 6,9)(0,1x + 2) = 0
c)	(4x + 2)(x2 + 1) = 0 	d)	(2x + 7)(x – 5)(5x + 1) = 0
e)	(x – 1)(2x + 7)(x2 + 2) = 0	f)	(4x – 10)(24 + 5x) = 0
g)	(3,5 – 7x)(0,1x + 2,3) = 0	h)	(5x + 2)(x – 7) = 0
i)	15(x + 9)(x – 3) (x + 21) = 0	j)	(x2 + 1)(x2 – 4x + 4) = 0
k)	(3x – 2) = 0	l)	(3,3 – 11x)= 0
2.	a)	(3x + 2)(x2 – 1) = (9x2 – 4)(x + 1)	b)	x(x + 3)(x – 3) – (x + 2)(x2 – 2x + 4) = 0
c)	2x(x – 3) + 5(x – 3) = 0	d)	(3x – 1)(x2 + 2) = (3x – 1)(7x – 10)
e)	(x + 2)(3 – 4x) = x2 + 4x + 4	f)	x(2x – 7) – 4x + 14 = 0 
g)	3x – 15 = 2x(x – 5)	h)	(2x + 1)(3x – 2) = (5x – 8)(2x + 1)
i)	0,5x(x – 3) = (x – 3)(1,5x – 1)	j)	(2x2 + 1)(4x – 3) = (x – 12)(2x2 + 1)	
k)	x(2x – 9) = 3x(x – 5)	l)	(x – 1)(5x + 3) = (3x – 8)(x – 1)
m)	2x(x – 1) = x2 - 1	n) 	(2 – 3x)(x + 11) = (3x – 2)(2 – 5x)	
o)	p)	
q)	r)	
s)	(x + 2)(x – 3)(17x2 – 17x + 8) = (x + 2)(x – 3)(x2 – 17x +33)
3.	a)	(2x – 5)2 – (x + 2)2 = 0	b)	(3x2 + 10x – 8)2 = (5x2 – 2x + 10)2 
c)	(x2 – 2x + 1) – 4 = 0 	d)	4x2 + 4x + 1 = x2
e)	(x + 1)2 = 4(x2 – 2x + 1)2	f)	(x2 – 9)2 – 9(x – 3)2 = 0
g)	9(x – 3)2 = 4(x + 2)2	h)	(4x2 – 3x – 18)2 = (4x2 + 3x)2
i)	(2x – 1)2 = 49	j)	(5x – 3)2 – (4x – 7)2 = 0
k)	(2x + 7)2 = 9(x + 2)2	l)	4(2x + 7)2 = 9(x + 3)2
m)	(x2 – 16)2 – (x – 4)2 = 0	n)	(5x2 – 2x + 10)2 = (3x2 + 10x – 8)2
o)	p)