Kiểm tra môn đại số 8 thời gian: 45 phút Trường THCS Thượng Lan

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Trường THCS Thượng Lan
Lôùp : 8……
Hoï & Teân :……………………………………………
 KIEÅM TRA M ÔN ÑAÏI SOÁ 8
Thời gian: 45 phút
 Thø …… ngµy……. th¸ng ……. N¨m 2008

	
 Điểm Lời phê của thầy , cô giáo





BAØI LAØM ÑEÀ SOÁ 1
I/ TRAÉC NGHIEÄM : (3 ñieåm). 
1) Gheùp moãi doøng ôû coät traùi vôùi keát quaû ôû coät phaûi ñeå ñöôïc moät keát quaû ñuùng:
a) x – y

1) (x - y ) .( x + xy + y) 
b) (x – 2 )

2) (x – y ).( x + y)
c) x – y

3) x + 9x + 27x + 27
d) (x + 3 ) 

4) (x – 2 ). ( x + 2x + 4)


5) x – 4x + 4

2) Khoanh troøn chöõ caùi ñöùng tröôùc caâu traû lôøi ñuùng :
a) Ña thöùc 2x – 1 – x ñöôïc phaân tích thaønh :
A/ (x – 1 ) 	B/ – (x + 1 ) 	C/– (x – 1 ) 	D/ (– x – 1 ) 
b) Ruùt goïn bieåu thöùc x.(x – y ) + y.(x – y ) ñöôïc :
A/ x + y	B/ x– y	C/ y– x	B/ – y– x	
c) Keát quaû cuûa pheùp chia ña thöùc : 2xy +6xy – 4xy cho ña thöùc 2xy laø : 
A/ 2x – 4xy + 1	B/ x – xy + 5	C/ x +3xy – 2y 	D/ Moät keát quaû khaùc
d) KÕt qu¶ ph©n tÝch ®a thøc 3x - 12x thµnh nh©n tö lµ
A. 3x( x- 4) B. 3x(x – 2) C. 3x( x + 2) (x – 2) D. 3( 3x – 2) ( 3x + 2)
II/ TÖÏ LUAÄN: (7 ñieåm). 
Baøi 1: (1,5ñieåm) Thöïc hieän pheùp tính:
a, 4x (5x2 - 2x -1)
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a , ( x +3y ) (x2 – 2xy +y ) …………………………………………………………………………………………………
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Baøi 2 : (2ñieåm) Phaân tích ña thöùc thaønh nhaân töû :
a) x– y–2x + 2y
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b) x– 6x + 5 
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Baøi 3 : (2ñieåm) Thöïc hieän pheùp chia
a) (3x2y2 + 6x2y3 - 12xy) : 3xy
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b) (x3-3x2+5x -6): (x2 – x + 3 )
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Baøi 4 : (1ñieåm) Vôùi giaù trò naøo cuûa m ñeå ña thöùc : x4 - 2x3 + 3x2 - 4x + m chia heát cho ña thöùc: x+2
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Baøi 5 : (0,5ñieåm)Chöùng minh raèng : x – 12x + 50 > 0 vôùi moïi x Î R 
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 Thø …… ngµy……. th¸ng ……. N¨m 2008
 KIEÅM TRA MÔN ÑAÏI SOÁ 8
Thời gian: 45 phút
Trường THCS Thượng Lan
Lôùp : 8……
Hoï & Teân :……………………………………………
 
 	
 Điểm Lời phê của thầy , cô giáo






BAØI LAØM ÑEÀ SOÁ 2
I/ TRAÉC NGHIEÄM : (3 ñieåm). 
Caâu 1 : Gheùp moãi doøng ôû coät traùi vôùi keát quaû ôû coät phaûi ñeå ñöôïc moät keát quaû ñuùng:
a) (x – y ) .( x + xy + y) 

1) x + 2xy + y
b) (x +y )

2) x + 3x y + 3xy + y 
c) (x – y ).( x + y) 

3) x+ y 
d) (x + y ) 

4) x – y 


5) x – y 
Caâu 2: Khoanh troøn chöõ caùi tröôùc caâu traû lôøi ñuùng :
1) x.( 2x ) baèng:
A/ 3x – 1	 B/ 3x- x	C/ 3x+ x 	D/ x– x 
2) x – x = 0 coù :
A/ x = 0	B/ x =1	C/ x = 0 ; x = 1	 D/ x = 0 ; x = – 1
3) 10xyzchia heát cho ña thöùc :
A/ 7xyz	B/ 5xyz	C/ 2xyz	D/ 10xyzt
4) (6x – 8x – 2x) : ( – 2x ) baèng :
A/ 3x – 4x – 1 B/ – 3x – 4x – 1 C/ 3x – 4x +1 	 D/ – 3x + 4x +1
II/ TÖÏ LUAÄN: (7 ñieåm). 
Baøi 1 : (1,5ñieåm)Thöïc hieän pheùp tính:
a) ( x2 -2xy +4 ).(2x y) 
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b) (x2 + 3x + 2).(x+3)
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Baøi 2 : (2ñieåm)Phaân tích ña thöùc thaønh nhaân töû :
a) b– c+ b + c
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b)( x+ 9) –36x 
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Baøi 3 : (2ñieåm)Thöïc hieän pheùp chia 
a) (-18x3y5 + 12x2y2 - 6xy3) : 6xy ……………………………………………………………………………………………
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b)(2x3 - 5x2 +9x – 14):(x - 2 )
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Baøi 4 : (1ñieåm)Vôùi giaù trò naøo cuûa a ñeå ña thöùc : 6x- 7x– x + a chia heát cho ña thöùc : 2x + 1

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Baøi 5 : (0,5ñieåm)Chöùng minh raèng : – x + 10x – 30 <0 vôùi moïi x Î R 
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 Thø …… ngµy……. th¸ng ……. N¨m 2008 
Trường THCS Thượng Lan
Lôùp : 8……
Hoï & Teân :……………………………………………
 KIEÅM TRA MÔN ÑAÏI SOÁ 8
Thời gian: 45 phút

 Điểm Lời phê của thầy , cô giáo
	
 
 	



BAØI LAØM ÑEÀ SOÁ 3
I/ TRAÉC NGHIEÄM : (3 ñieåm). 
Baøi 1 : Gheùp moãi doøng ôû coät traùi vôùi keát quaû ôû coät phaûi ñeå ñöôïc moät keát quaû ñuùng:
a) x + 1 

1) x – 4 
b) (x + 1 ) 

2) x – 8 
c) (x – 2 ).( x + 2) 

3) x+ y 
d) x – 6x + 12x – 8 

4) (x + 1)(x – x + 1)
e) (x – 2 ). ( x + 2x + 4)

5) x + 4x + 4 
f) (x + 2) 

6) ( x – 2 ) 


7) x + 3x +3x + 1


8) ( x – 4) 
Caâu 2: Khoanh troøn caâu ñuùng. 
a) Tính : (-4x)(5x-2y)=?
A. –20x2-8xy	 B. 20x2 +8xy	C. –20x2+8xy	D. Caû a,b,c ñeàu sai.
b) Kết quả của phép tính 15x2y2z : (3xyz) là
A. 5xyz
B. 5 x2y2z
C. 15xy
D. 5xy
c) Kết quả của phép tính (2x2 - 32) : (x - 4) là
A. 2(x – 4)
B. 2 (x + 4)
C. x + 4
D. x – 4
II/ TÖÏ LUAÄN: (7 ñieåm). 
Baøi 1 : (1,5ñieåm)Thöïc hieän pheùp tính:
a) (5x2y – 3xy2+2x).4xy
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b) (2a – 1)(a2 – 5 +2a) 
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Baøi 2 : (2ñieåm) Phaân tích ña thöùc thaønh nhaân töû :
a) xy + xz –2y – 2z
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b) 25 – x+ 4xy – 4y 
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 Baøi 3 : (2ñieåm)Thöïc hieän pheùp chia 
(2x2y3 + 5x3y2 - 6x2y2):5xy2
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b)(x4 + 2 x3 + 5x2 +10 x – 18) : (x – 1)
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Baøi4 : Vôùi giaù trò naøo cuûa a ñeå ña thöùc : x+ x– x + a chia heát cho ña thöùc : x + 2
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Baøi 5 : (0,5ñieåm)Chöùng minh raèng :4 x + 4x+ 11 >0 vôùi moïi x Î R 
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 Điểm Lời phê của thầy , cô giáo
Trường THCS Thượng Lan
Lôùp : 8……
Hoï & Teân :……………………………………………
 KIEÅM TRA MÔN ÑAÏI SOÁ 8
Thời gian: 45 phút
	 Thø …… ngµy……. th¸ng ……. N¨m 2008 

 Điểm Lời phê của thầy , cô giáo
	
 
 	



BAØI LAØM ÑEÀ SOÁ 4 
I/ TRAÉC NGHIEÄM : (3 ñieåm).
Caâu 1: H·y ghÐp mçi biÓu thøc ë cét A víi mét biÓu thøc ë cét B ®Ó ®­îc ®¼ng thøc ®óng 
 A 

 B 
 1, (x –y) (x+y )

a , x2 +2x +1 
 2, (x +1 ) 2 

b, 9x2 +6x +1 
 3, (3x -1 )2 

c, 9x2 -6x +1 
 4, (3x – 1 )3

d, x2 –y2


e , y2 –x2 


f, 27x3 – 27x2+ 9x - 1
 Caâu 2:Khoanh troøn chöõ caùi tröôùc caâu traû lôøi ñuùng :
1) Phaân tích ña thöùc x ( x – 2 ) + x – 2 thaønh nhaân töû : 
A/ (x – 2 ) . x	B/ (x – 2 ).x	 	C/ x (2x – 4 ) 	D/ (x – 2 ).( x+ 1) 
2) Ñôn thöùc 8xyz chia heát cho ñôn thöùc naøo 
A/ 16xy	B/ 2xyz	C/ 0,3x y5 	D/ xyz 
 3) Tích cuûa ñôn thöùc – 5x vaø ña thöùc 2x + 3x – 5 laø :
A/ 10x–15x+25x B/ –10x–15x+25x C/ –10x–15x– 25x D/ Moät keát quaû khaùc
4) Giaù trò cuûa bieåu thöùc : ( - 5x y ) : 10x y taïi x = 100 , y = laø :
	A/ – 5	B/ 	C/ 5	D/ 
II/ TÖÏ LUAÄN: (7 ñieåm).
Baøi 1 : (1,5ñieåm)Thöïc hieän pheùp tính:
a) (3xy2z + 5xyz2+2xy).6xyz2
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b) (2x – 3)(x2 + 6 – 2x) 
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Baøi 2: (2ñieåm)Phaân tích ña thöùc thaønh nhaân töû :
a) 3x+ 3xy – x – y
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b) 32 x – 18x 
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Baøi 3 : (2ñieåm)Thöïc hieän pheùp chia 
a) (3xy4 – 2xy3 +10 xy2 ) :4xy2 ……………………………………………………………………………………………
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b) (x3 +3x2 – 4x - 12) : ( x2 + x – 6)
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Baøi 4: Vôùi giaù trò naøo cuûa a ñeå ña thöùc : 5x – 3x+ 7x– x + a chia heát cho ña thöùc : x – 2 
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Baøi 5 : Chöùng minh raèng bieåu thöùc :A = x + 6 x + 11 > 0 vôùi moïi xÎ R 
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ÑAÙP AÙN ÑEÀ SOÁ 1
I/ TRAÉC NGHIEÄM : (3 ñieåm).
Caâu 1: gheùp ñuùng moãi yù cho 0,25ñ
a -> 2 , b -> 5 , c -> 1 , d -> 3 
Caâu 2: Moãi yù ñuùng cho 0,5 ñieåm
a) C b) B c) C d) A
II/ TÖÏ LUAÄN: (7 ñieåm).
Baøi 1: (1,5ñieåm) Thöïc hieän pheùp tính:
a, 4x (5x2 - 2x -1)
= 4x.5x2 – 4x.2x -4x.1	0,25ñ
= 20x3 – 8x2 -4x 0,2ñ
a , ( x +3y ) (x2 – 2xy +y ) 
= x(x2 – 2xy +y ) + 3y(x2 – 2xy +y ) 0,25ñ
=x3 – 2 x2y +xy + 3 x2y – 6xy2 +3y2 0,5ñ
= x3 + x2 +xy – 6xy2 +3y2 0,25ñ
Baøi 2 : (2ñieåm) Phaân tích ña thöùc thaønh nhaân töû :
a) x– y–2x + 2y
= (x– y) – (2x - 2y) 0,5ñ
= (x + y)( x - y) – 2(x - y)	0,25ñ
= (x - y) (x + y – 2)	0,25ñ
x– 6x + 5
 = x– x – 5x+ 5 0,25ñ
 = (x– x)- (5x- 5) 0,25ñ
 = x(x – 1) – 5(x – 1)	0,25ñ
 = ( x – 1)(x – 5)	0,25ñ
Baøi 3 : (2ñieåm) Thöïc hieän pheùp chia
a) (3x2y2 + 6x2y3 - 12xy) : 3xy
= 0,25ñ
= xy + 2x y2 – 4 0,25ñ
b) (x3-3x2+5x -6): (x2 – x + 3 )
 x3 - 3x2 + 5x - 6 x2 – x + 3
 x3 – x2 + 3x x – 2 
 -2 x2 + 2x – 6 
 -2 x2 + 2x – 6
 0 ( moãi böôùc ñuùng cho 0,5ñ)
Baøi 4 : (1ñieåm) Vôùi giaù trò naøo cuûa m ñeå ña thöùc : x4 - 2x3 + 3x2 - 4x + m chia heát cho ña thöùc: x+2
 x4 - 2x3 + 3x2 - 4x + m x+2
 x4 + 2x3 x3- 4x2+11x – 26 
	- 4x3 + 3x2 - 4x + m
 - 4x3 – 8x2 
	11x2 - 4x + m
	11x2+ 22x	 0,5ñ
	- 26x + m
	- 26x - 52
 m+ 52 
Ñeå x4 - 2x3 + 3x2 - 4x + m chia heát cho ña thöùc: x+2 thì m+ 52 = 0 Þ m = - 52 	0,5ñ
Baøi 5 : (0,5ñieåm)Chöùng minh raèng : x – 12x + 50 > 0 vôùi moïi x Î R 
x – 12x + 50 = x – 2.x.6 + 36 +14
 = x – 2.x.6 + 62 + 14 
 = (x – 6)2 +14 0,25ñ
Vì (x – 6)2 ³ 0 vôùi moïi x Î R neân (x – 6)2 +14 ³ 14 > 0 vôùi moïi x Î R 
Hay x – 12x + 50 > 0 vôùi moïi x Î R 0,25ñ


ÑAÙP AÙN ÑEÀ SOÁ 2
I/ TRAÉC NGHIEÄM : (3 ñieåm).
Caâu 1: gheùp ñuùng moãi yù cho 0,25ñ
a -> 5 , b -> 1 , c -> 4 , d -> 2 
Caâu 2: Moãi yù ñuùng cho 0,5 ñieåm
1) B 2) C 3) A 4) D
II/ TÖÏ LUAÄN: (7 ñieåm). 
Baøi 1 : (1,5ñieåm)Thöïc hieän pheùp tính:
a) ( x2 -2xy +4 ).(2x y) 
= x2.2x y - 2x y. 2x y + 4. 2x y 0,25ñ
= 2 x3 y – 2 x2 y2 + 8xy 0,25ñ
b) (x2 + 3x + 2).(x+3)
= x(x2 + 3x + 2) + 3(x2 + 3x + 2) 0,25ñ
= x3 + 3x2 + 2x + 3x2 +9x +6 0,5ñ
= x3 + 6x2 + 11x +6 0,25ñ

Baøi 2 : (2ñieåm)Phaân tích ña thöùc thaønh nhaân töû :
a) b– c+ b + c
= ( b– c) + (b + c) 0,5ñ
= (b + c) (b - c)+ (b + c)	0,25ñ
= (b + c)(b – c + 1) 0,25ñ
b)( x+ 9) –36x 
= ( x+ 9) - (6x)	 0, 5ñ
= (x+ 9 + 6x)( x+ 9 - 6x) 0,25ñ
=( x+ 3) ( x- 3) 	0,25ñ
Baøi 3 : (2ñieåm)Thöïc hieän pheùp chia 
a) (-18x3y5 + 12x2y2 - 6xy3) : 6xy 
= -18x3y5: 6xy + 12x2y2:6xy - 6xy3 :6xy 0,5ñ
= - 3 x2y4 + 2 xy	- y2 0,5ñ
b)(2x3 - 5x2 +9x – 14):(x - 2 )
 2x3 - 5x2 + 9x – 14 x - 2 
 2x3 - 4x2 2 x2 –x +7
 - x2 + 9x – 14
 - x2 + 2x
 7x – 14
 7x – 14
	0
Vaäy (2x3 - 5x2 +9x – 14):(x - 2 ) = 2 x2 –x +7
(Moãi böôùc ñuùng vaø traû lôøi cho 0,25ñ)
Baøi 4 : (1ñieåm)Vôùi giaù trò naøo cuûa a ñeå ña thöùc : 6x- 7x– x + a chia heát cho ña thöùc : 2x + 1
 6x- 7x– x + a 2x + 1
 6x- 7x	 3 x2 – 5x +2
 - 10x– x + a 
 - 10x–5 x	0,5ñ
 4x + a
 4x + 2
	a - 2
Ñeå 6x- 7x– x + a chia heát cho ña thöùc : 2x + 1 thì a – 2 = 0 Þ a = 2 0,5ñ
Baøi 5 : (0,5ñieåm)Chöùng minh raèng :- x + 10x – 30 <0 vôùi moïi x Î R 
- x + 10x – 30 = -( x - 10x + 30) = - (x- 5)2 -5 0,25ñ
Vì (x – 5)2 ³ 0 vôùi moïi x Î R Þ - (x – 5)2 £ 0 vôùi moïi x Î R neân - (x- 5)2 -5 £ - 5 <0 vôùi moïi x Î R 
Hay - x + 10x – 30 <0 vôùi moïi x Î R	0,25ñ

 ÑAÙP AÙN ÑEÀ SOÁ 3
I/ TRAÉC NGHIEÄM : (3 ñieåm).
Caâu 1: gheùp ñuùng moãi yù cho 0,25ñ
a -> 4 , b -> 7 , c -> 1 , d -> 6 , e -> 2 , f -> 5
Caâu 2: Moãi yù ñuùng cho 0,5 ñieåm: a) C b) D c) B 
II/ TÖÏ LUAÄN: (7 ñieåm). 
Baøi 1 : (1,5ñieåm)Thöïc hieän pheùp tính:
a) (5x2y – 3xy2+2x).4xy
= 5x2y .4xy – 3 xy2. 4xy + 2x.4xy 0,25ñ
= 20x3y2 – 12x2y3 + 8x2y 0,25ñ
b) (2a – 1)(a2 – 5 +2a) 
 = 2a(a2 – 5 +2a) – 1(a2 – 5 +2a) 0,25ñ
= 2a3 – 10a + 4a2 – a2 +5 – 2a 0,5ñ
= 2a3 + 3a2 – 12a +5 0,25ñ
Baøi 2 : (2ñieåm) Phaân tích ña thöùc thaønh nhaân töû :
a) xy + xz –2y – 2z
= ( xy+xz) – (2y-2z) 0,5ñ
= x(y+z) – 2(y+z) 0,25ñ
= (y + z)(x – 2) 0,25ñ
b) 25 – x+ 4xy – 4y 
 = 25 – (x- 4xy + 4y)	0,5ñ
= 52 – ( x – 2y)2 0,25ñ
= (5 + x – 2y)(5 – x + 2y) 0,25ñ
 Baøi 3 : (2ñieåm)Th

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